Saving die space is important for yields. You realize its a monolithic chip, right? Sure they can build a huge die with 16 p cores, but then the actual cost would be stupendous.
No it wouldn't. 11900K is larger than Alder Lake 8+8. And considering how big GPU are, answer is very simple.
For comparison:
Zen3 chiplet: around 80mm2
Ryzen 9 6900HS: 208 mm2
6900XT GPU: 520mm2
And that 6900XT is GPU only, not whole card.
What do you mean its not even big? Its freaking huge, probably at the limit of what is cost efficient to produce. The zen 3 dies are less than half the size, lol.
Becaus aroudn 200mm2 is not big at all. If around 200mm2 is big, then what is Nvidia's 6080 GPU, 628 mm2.
And too expensive? Even assuming very poor 50% yields and around 300mm2 die size (die size may be larger but yields much better too), that makes around 100 chips per wafer. Assuming wafer cost 10K$, that makes 100 dollars per chip. Still very profitable.
Once again, you have absolutely no clue what you are talking about.
Sir, does the 5950x consume double as much power as the 5800x? No? Then why the heck do you think a hypothetical 16p core intel would? You do understand they can limit the cpu so it consumes as much power as they want to consume, RIGHT? You do realize that the 12700 has twice the pcores + ecores yet it has the same tdp as the 12100? So wtf are you talking about???????
Its pointless talking to you honestly, your amd glasses are just blinding you.
I didn't say anything about clock speeds, did I? Of course they can limit power consumption but why put more cores and then lower clock speeds so much it's effectively pointless?
TDP is not power consumption. Never have been.
How about learning basics next time?