IP fragmentation and total length

By Jskid
Oct 26, 2012
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  1. I am so confused by the answer to this question. If the MTU is 601 bytes how come the total length for the first two are 596, shouldn't they be 601?

    Shouldn't the fragment offset for the second fragment be 601/8=75.125?

    How do you know what the MF flag should be?

    I looked up all these terms on wikipedia and understand them but I still don't get this question.

    [​IMG]
    upload picture
  2. jobeard

    jobeard TS Ambassador Posts: 13,026   +221

    Hmm; goofy question in the first place as MTU must be multiples of 8 :)

    second, the no headers option MUST apply to optional stuff, as the packet destination is in the header portion of the packet while total length = (payload + header) <= MTU

    That's all I can offer, ie never took TCP 101 :sigh:


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